Math, asked by kanika6666, 10 months ago


A dealer sold two types of goods for 10,000 each. On one of them, he lost 20% and on the other, he gained 20% find his gain or loss per cent on the entire transaction.

Answers

Answered by amikkr
8

The seller incurs a loss of 4% overall on both goods.

  • Two goods are sold at Rs. 10000 each.
  • On one the seller gains 20% and on one 20% .
  • We have to find the overall gain or loss percentage.
  • Let us assume the cost price of first be x_1 and other be x_2.
  • We have to calculate the profit and loss on the goods.
  • Profit percentage = \frac{10000-x_1}{x_1} × 100 = 20

10000-x_1 = 0.20x_1

10000 = 1.2x_1

x_1 = 10000/1.2 = 8333.33 Rs.

  • Therefore cost price of the product where the seller gains 20% is Rs. 8333.33.
  • Loss percentage = \frac{x_2-10000}{x_2} × 100 = 20

x_2-10000  = 0.2x_2

0.8x_2  = 10000

x_2 = Rs. 12500

  • Therefore cost price of the product where the seller loses 20% is Rs. 12500.
  • Now we have to calculate the net profit or loss percentage, we find the total cost price of two goods,
  • Total cost price = 8333.33 + 12500 = 20833.33 Rs.
  • Now ,Profit on article 1 - Loss on article 2 = Net gain

(10000-8333.33) - (12500-10000) = Net gain

Net gain = 1666.67 - 2500 = -833.33

  • Therefore the seller gains a loss of 833.33 Rs. total on both goods.
  • Now net loss percentage = \frac{Net \ loss}{total \ cost \ price} × 100  

Net loss percentage = \frac{833.33}{20833.33} × 100 = 4%

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