Math, asked by Balajinaik3824, 1 year ago

A dealer sold two types of goods for rs 10,000 each. On one of them, he lost 20% and on the other he gained 20%. His gain or loss per cent in the entire transaction was

Answers

Answered by Dynamo712
5

The dealers gain / loss percent is 0%.

I hope it will help you

Answered by slicergiza
13

Answer:

He has 4% loss.

Step-by-step explanation:

Given,

The selling price of first good = 10,000

Loss % = 20%,

Since,

loss\% = \frac{CP-SP}{CP}\times 100

20=\frac{CP-10000}{CP}\times 100

0.2CP = CP-10000

0.8CP = 10000

\implies CP = \frac{100000}{8}=12500

So, the Cost price of first good is 12,500 rupees.

Now, the selling price of second good = 10,000

Gain % = 20%,

Since,

gain\% = \frac{SP-CP}{CP}\times 100

20=\frac{10000-CP}{CP}\times 100

0.2CP = 10000 - CP

1.2CP = 10000

\implies CP = \frac{100000}{12}=\frac{25000}{3}

i.e. the Cost price of second good is \frac{25000}{3} rupees,

So, total cost price = 12500+\frac{25000}{3}=\frac{37500+25000}{3}=\frac{62500}{3}

While total selling price = 10,000 + 10,000 = 20,000 rupees,

Thus, total change percentage = \frac{20,000 - \frac{62500}{3}}{\frac{62500}{3}}\times 100=\frac{60000 - 62500}{62500}\times 100 = -\frac{250000}{62500}=-4\%

Hence, he had 4% loss in entire transaction.

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