Question

A deci-molar solution of urea is diluted 100 times. It's final molarity is -
(A) 10-2
(B) 10-3
(C) 10
(D) 100
​

Answer 1

The final molarity of deci-molar solution of urea is $10^{-3}$.

Explanation:

Given:

$M_1 = \frac{1}{10}$

To find:

Final molarity $(M_2)$ = ?

Formula to be used:

$M_1V_1=M_2V_2$

Calculation:

$M_1V_1=M_2V_2$

$\frac{1}{10}$ × V = $M_2\times 100V$

On cancelling V on both the side, it gives:

$\frac{1}{10} = M_2\times 100$

As the value of $M_2$ is required,

$M_2=\frac{1}{10\times100}$

$M_2=\frac{1}{1000}$

$M_2 = 0.001 = 10^{-3}$

Conclusion:

Thus the final molarity of the given urea solution is calculated as 0.001 or $10^{-3}$M. Hence option B is identified as the correct answer.

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