Math, asked by an05, 1 day ago

A decided to build a house in 70 days. A employed 25 workers in the beginning and 25 more worker after 60 days to complete the work. Find the delay (in days) if no additional workers would have been employed.​

Answers

Answered by MAITHILLIRUPESHPATIL
1

Answer:

5 days behind the schedule they would have

finished the work.

Step-by-step explanation:

Here's the solution to the problem:

Total men working in this project of

farmhouse are 60men.ln the starting only

40men were there and after 10 days 20

more men were employed to finish the work

in 20 days duration.

Total men= 40+20-60 men.

60men doing the rest of the work in 20-10=

10 days.

When 40 men doing the remaining of the

work=(10*60)/40=15 days.

So, according to the above question if the

additional number of employees were not

employed then the work would have lasted

15-10-5 days longer.

Answered by shivamvishwakarma6b
1

Answer:

100 men worked for 35 days and 200 men worked for 5 days.

So, total mandays required to finish the job = 100 * 35 + 200 * 5 = 4500

So, 100 men worked only, the job would have finished in 4500/100 = 45 days.

Days behind the schedule = 45 -40 = 5 days. Ans.

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