Chemistry, asked by kunalsinha4042, 10 months ago

A decimolar solution of h2so4 is prepared. Find the normality and strength of solutions

Answers

Answered by Anonymous
6

Answer:

water is added to H2 S o4 then solution will be diluted that is H2 S o4 is diluted so the its strength will decrease ...

Explanation:

Answered by brainlysme13
0

The normality of the solution is 0.2 N and the strength of the solution is 9.8097 grams per liter.

Given,

Decimolar solution of H2SO4 is prepared

To Find,

Normality

Strength of solution

Solution,

We have been given that a decimolar solution of H2SO4 is prepared.

That is, the molarity of the solution is M/10

Or, 0.1 moles of H2SO4 are dissolved in 1 L of water.

If you know the molarity of an acid solution, you can easily convert it to normality by multiplying molarity by the number of hydrogen ions in the acid

The no. of hydrogen ions in this acid = 2.

Therefore, the normality of the given H2SO4 solution is given by:

⇒ normality = 2 × 0.1

⇒ normality = 0.2 N

Acid strength is a measurement of an acid's capacity to release its H+ ion.

Mathematically, the strength of a solution is given by the following relationship:

⇒ S = m/V

where S is the strength of the solution, m is the mass of solute in grams and V is the volume of the solution in liters.

We know that the molar mass of H2SO4 is 98.079 g/mol

⇒98.097 grams of H2SO4 are in 1 mole of H2SO4

⇒98.097 × 0.1 grams of H2SO4 are in 0.1 mole of H2SO4

⇒9.8097 grams of H2SO4 are in 0.1 mole of H2SO4

Therefore, strength of the solution,

⇒ S = 9.8097/1 g/L

⇒ S = 9.8097 g/L

#SPJ3

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