Question

A deep-sea exploring ship is pulling up a diver at the rate of 25 feet per minute. The diver is 200 feet below sea level. How deep was the diver 10 minutes ago?

Answer 1

Given :

The rate of pulling = 25 feet/min

The present depth of the driver = 200 feet

To Find :

The depth of driver 10 min ago

Solution :

Let The depth 10 min ago = x ft

∵ Distance = Speed × Time

So,

Depth 10 min ago = present depth × $(1-\dfrac{rate}{100}) ^{time}$

Or,  x = 200 ft × $(1-\dfrac{25}{100}) ^{10}$

Or,  x = 200 ft × $(\dfrac{3}{4} ) ^{10}$

Or,  x = 200 ft × 0.0563

∴    x = 11.26 feet

Or ,  depth of driver 10 min ago = x = 11.26 feet

Hence, The depth of driver 10 min ago is 11.26 feet Answer

Answer 2

Answer:

-175

Step-by-step explanation:

because you have to subtract to get your answer