Math, asked by prashantpete4, 2 months ago

A deep-sea exploring ship is pulling up a diver at the rate of 25 feet per

minute. The diver is 200 feet below sea level. How deep was the diver

10 minutes ago?​

Answers

Answered by ayushkumarsingh28
1

Answer:

450

Step-by-step explanation:

Since tge diver is being pulled up, measuring his movement for the past

10

minutes requires that we use

25

for the movement over those

10

minutes. So, his depth

10

minutes ago is given by the expression

200

25

(

10

)

200

250

450

So,

10

minutes ago, the diver was

450

feet below sea level.

Answered by bludoplphin21
3

Answer:

450 ft

Step-by-step explanation:

ok so,

rate at which diver is being pulled up= 25 ft/ min

level at which he is right now= 200 ft below sea level

level he was at 10 mins ago = ?

     distance travelled in:

          1 min= 25 ft

          10 min= 25 x 10 = 250 ft

         

level at which he was 10 mins ago = level at which he is at right now + distance travelled in 10 mins

=> (200 + 250)ft = 450 ft

∴ level at which diver was at 10 min ago = 450 ft below sea level

if you have any doubt please ask. Hope this explains your question. :)

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