a deer escapes from a leopard and runs away ina straight line with constant Velocity. the leopard again starts chasing the deer when the deer has run a distance of 64m. the leopard starts with the initial speed of 30m/s but due to fatigue it has to reduce its speed and it does so by reducing speed uniformly by 4m/s every 2 second.
at what speed should deer run to save it's life.
@rajshuklakld. your answer is correct.
plz repost it answer in full deatail.
BTW the answer is 14m/s. it is not the case of uniform acceleration. so don't try to be oversmart and apply eq of motion.
correct detailed solution will be marked brainliesr
Answers
Concept:-The thing which only matters in this question is the moment at which they will meet,the speed of deer must be larger than speed of leopard,so that leopard should not be able to catch the deer
Let the time at which they will meet be T
then, distance travelled by leopard at time
s=30×t-1/2 ×2 ×t^2
s=30t-t^2
velocity of leopard at t=>v=30-2t
here a=-4/2=-2m/s^2
the velocity of deer at time t will be a bit only greater than that of leopard, because it asked the minimum velocity
so,the velocity of deer should be greater than 30-2t
since the speed is very little greater than 30-2t,so we will take 30-2t as the approx velocity of deer
now,
distance travelled by deer=(30-2t)×t=>30t-2t^2
now,
visualizing the condition we can write
distance travelled by deer+64=distance travelled by leopard
30t-2t^2+64=30t-t^2
t=8
velocity of leopard at t =30-2t=30-2×8=14m/s
as said above the velocity of deer should be greater than 30-2t i.e 14m/s
[The acceleration of leopard is uniform retardition , that's why we can use equation of uniformly accelerated motion]
Answer:
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