A defibrillator passes 12.0 A of current through the torso of a person for 0.0100 s. How much charge moves? (b) How many electrons pass through the wires connected to the patient?
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Answers
Answer:check the attachment below, hope it would be helpful!
Explanation:
Answer:
The current that passes through defibrillator is 0.12 coulomb and the number of electrons is
7.5*10^17
Explanation:
Given
Current that passes through defibrillator is 12A
Time for which the current passes is 0.0100 s
Charge that moves Q= I*T
Q= 12*0.0100
Q= 0.12 coulomb
2) Number of electrons that pass through the wire is
N=Q/q
N=0.12/-1.6*10^-19
N= 7.5*10^17
We know that
Current is charge/time
so,charge is current/time.
Also the SI unit of current is Ampere
SI unit of time is second
SI unit of charge is coulomb
electronic charge is -1.6*10^-19
The electronic charge is taken as negative as the electron itself is negatively charged.
1 coulomb is defined as the amount of electricity that 1 ampere current carries in one second.
1 ampere is defined as the 1 coulomb charge flowing in 1 second.
For more references:-
https://brainly.in/question/2926652?utm_source=android&utm_medium=share&utm_campaign=question
https://brainly.in/question/7138498?utm_source=android&utm_medium=share&utm_campaign=question
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