Question

(a) Define uniform acceleration. What is the acceleration of a body moving with uniform

velocity?

(b) A particle moves over three quarters of a circle of radius r. What is the magnitude of its

displacement?

Answer 1

Heya..

A. When velocity of a body increases or decreases with uniform rate called as uniform acceleration.

If body moving with uniform velocity..... Then u = v

(initial velocity) = (final velocity)

Hence a = (v-u) /t.

= 0/t

= 0.

B. A particle moves over three quarters of a circle of radius r. What is the magnitude of its

displacement?

Displacement is shortest distance from initial point.

Suppose ur question is as clock diagram.

According to this question,.

Body moves from 3 o clock to 12 to 9 and finally to 6 o clock.

Then displacement^2 = under root (r^2 + r^2)

=) d^2 = 2 r^2

=) d = = √2 r

Hope it's helpful to u.

Answer 2

Question (a)

Define Uniform Acceleration?

Uniform acceleration means that the change in velocity per unit of tine is always the same in terms of magnitude and direction.

What is the acceleration of a body moving with uniform  

velocity?

Since acceleration is rate of change of velocity over time,a body moving with uniform velocity will have 0 acceleration.

a=dv/dt

For uniform velocity dv=0

Hence a=0

Acceleration of a body moving with uniform velocity is zero

Question (b)

A particle moves over three quarters of a circle of radius r. What is the magnitude of its  displacement?

Radius of circle =r

Body moves over 3 quarters

Magnitude of displacement = the hypotenuse of the 4th quarter whose Base and perpendicular r both = r unit.

Then,

(Hypotenuse)² = base² +perpendicular²

H² =r² +r²

H^2=2r²  

H=√2r²

The magnitude of its displacement √2r²