Question

A deliveryman travels 36.0 m north, 28.0 m east, 18.0 m south, then takes an elevator 32.0 m up into a building. What is the magnitude of his displacement (in meters) from his starting point?

Answer 1

Answer:

46.17 m

Explanation:

Let the unit vectors along

• East = i
• North = j
• Vertically upwards = k

Displacement vector of delivery man can then be written as

D = 36j + 28i - 18j + 32k

= 28i - 18j + 32k

Magnitude of displacement of delivery man is

|D| = √(28² + 18² + 32²) m = 46.17 m