A dentist use a mirror in front of a decayed tooth at a distance of 4 cm from the tooth to get a 4 times magnified image. Use mirror formula to find the focal length and nature of mirror used. What is the nature of image?
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Hope this helps you buddy ,
ATQ , u = -4
magnification (m) = +4
m = -v/u ⇒ 4 = -v / -4 ⇒ 4 *-4 = -v
so , -16 = -v
v = 16 cm .................................................(i)
HERE IT'S CLEAR THAT IT IS A CONCAVE MIRROR BECAUSE IT ONLY GIVES ERECT MAGNIFIED IMAGE WHEN KEPT B/W F AND P
(Note that here v is (+ve) indicating that image is formed behind the mirror)
now using mirror's formula , we will find the focal length ,
1/f = 1/v + 1/u
1/f = 1/16 + (-1/4)
1/f = 1/16 - 1/4
1/f = 1-4/16
1/f = -3/ 16
f = -16/3
IMAGE IS VIRTUAL , ERECT AND MAGNIFIED , FORMED BEHIND THE MIRROR
MIRROR USED - CONCAVE MIRROR
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