a dentist uses a small concave mirror of focal length 3.0 CM and holds it at a distance of 2 cm from tooth what is the magnification of image..
fast guys
Answers
Answered by
67
Heya!!
Since it is a concave mirror,
So u( distance of object from mirror) = -2cm,
Focal length (f) = -3cm
Since 1/f = 1/u + 1/v
=) 1/-3 = 1/-2 + 1/v
=) - 1/3 + 1/2 = 1/v
=) 1/6 = 1/v
=) v (distance of image from mirror) = 6cm
Since magnification = - v/u
= - 6/-2
= 3
Hope it helps uh!!
Since it is a concave mirror,
So u( distance of object from mirror) = -2cm,
Focal length (f) = -3cm
Since 1/f = 1/u + 1/v
=) 1/-3 = 1/-2 + 1/v
=) - 1/3 + 1/2 = 1/v
=) 1/6 = 1/v
=) v (distance of image from mirror) = 6cm
Since magnification = - v/u
= - 6/-2
= 3
Hope it helps uh!!
Answered by
18
★Hello mate here is your answer...
1/f= 1/u+1/v»1/v=1/f - 1/u
» 1/v = 1/-3- 1/-2= 1/6
Magnification, m= Image distance/ object distance,
= - 6cm/-2cm
= 3 cm
★Hope this will help you«««
1/f= 1/u+1/v»1/v=1/f - 1/u
» 1/v = 1/-3- 1/-2= 1/6
Magnification, m= Image distance/ object distance,
= - 6cm/-2cm
= 3 cm
★Hope this will help you«««
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