.a) Derive an expression for acceleration due to gravity in terms of mass of the earth (M) and universal gravitation constant (G) (b) Where is the acceleration due to gravity is minimum and maximum on the surface of the earth?
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a) F = GMm/d^2 (Universal law of gravitation)
now F = mg (second law of newton)
mg = GMm/d^2
g = GM/d^2
G = 6*10^-11
M=6*10^24
d=6*10^6
=6 * 10^-11 * 6 * 10^24 / (6 * 10^6)^2
=36 * 10^13 /36 * 10^12
=10
Answer:10 m/s^2
b) the acceleration due to gravity is minimum over the equator and maximum near the poles
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