Question

a. Derive an expression for the equivalent resistance of three resistors R1, R2, R3 connected in parallel.(3) b. A battery of 12 V is connected to a series combination of resistors 3 Ω, 4 Ω, 5 Ω and 12 Ω. How much current flows through 12 Ω resistor?

Answer 1

Answer:

1/R1 + 1/R2 + 1/R3 = 1 / R. Similarly, For n number of resistors connected in parallel, The Total Equivalent resistance = 1/R1 + 1/ R2 + 1/Rn = 1 / R.