Question

(a) Derive an expression g = G M/R².
(b) The value of g is greater on poles or equator? Why?
(c) An object is thrown vertically upwards and rises to a height of 10 m. Calculate (i) the velocity with which the object was thrown upwards and (ii) the time taken by the object to reach the highest point.​

Answer 1

Answer:

Explanation:

a - f=mg and f=GMm/R2

mg = GMm/R2

shifting m -

g = GMm/R2*m

m gets cut so g = GM/R2

b - earth is bulky at equator and flattened at poles. Hence.

c - h=10m

    u = root2gh

       = root2*9.8*10

       = 14m/s

     

HOPE IT HELPED.

PLS MARK BRAINLIEST