Question

a) Derive the expression of lens maker formula.
b) A convex lens has a focal length of 25cm in air. When it is dipped in a liquid of refractive
index 4/3, its focal length is increased to 100cm. Find the refractive index of lens
material.
uit with = 3H. C= 27 uF and R= 30 32. at resonance,
1
= (4.1)
Tn​

Answer 1

Answer:

1/f=1/v-1/u

Explanation:

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