A design on the wall of room consist 1000tiles of shape of parallelogram. if altitude &base of each tile is 10cm &4cm respective ly find the cost of polishing the design at the rate $9.50per dm2.
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Answered by
2
Answer:
area of 1 tile=b*h=10*4=40 cm^2
area of 1000 tiles=40*1000=40000cm^2=4000 dm^2
Total cost=9.50*40000
=95*4000=380000$
Step-by-step explanation:
AdiN05517:
40000 cm² = 400 dm² not 4000
wrong answer
Answered by
3
Hi friend!
Answer:
First we will convert the units to one.
1cm = 1/10 dm
b = 10cm
h = 4cm
10cm = 1dm
4cm = 0.4m
Area of whole room = no. of tiles × area of each tile
= n × (b × h)
(Area of each tile = b × h)
(n = Total no. of tiles)
= 1000 × 1 = 0.4
= 1000 × 0.4
= 400dm²
Cost of polishing 1dm² = $9.50
Cost of polishing 400dm² = $9.50 × 400 = $3800
Therefore, the cost of polishing the tiles in the room = $3800 (₹273296).
Hope you found my answer helpful. Keep Smiling!
Answer:
First we will convert the units to one.
1cm = 1/10 dm
b = 10cm
h = 4cm
10cm = 1dm
4cm = 0.4m
Area of whole room = no. of tiles × area of each tile
= n × (b × h)
(Area of each tile = b × h)
(n = Total no. of tiles)
= 1000 × 1 = 0.4
= 1000 × 0.4
= 400dm²
Cost of polishing 1dm² = $9.50
Cost of polishing 400dm² = $9.50 × 400 = $3800
Therefore, the cost of polishing the tiles in the room = $3800 (₹273296).
Hope you found my answer helpful. Keep Smiling!
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