Question

a design on the wall of room consists of 1000 tiles of the shape of parallelogram. if altitude and base of each tile is 10 cm and 4 cm respectively

Answer 1

Answer is attached with in image form

Answer 2

Answer:

Rs. 3800

Step-by-step explanation:

Given : A design on the wall of room consists of 1000 tiles of the shape of parallelogram.

Altitude and base of each tile is 10 cm and 4 cm respectively

To Find :find the cost of polishing the design at the rate of ₹ 9.50 square dm.

Solution :

Height of 1 tile = 10 cm

Base of tile = 4 cm

Area of tile = $Base \times Height = 10 \times 4 = 40 cm^2$

Area of 1000 tiles = 40 * 1000 = 40000 sq.cm.

1 sq.cm = 0.01 sq.dm

So,  40000 sq.cm. = $40000 \times 0.01=  400 dm^2$

Cost of polishing 1 sq.dm =  Rs.9.50

So, Cost of polishing 400 sq.dm = $9.50 \times 400 =3800$

Hence the cost of polishing the design at the rate of ₹ 9.50 square dm is Rs. 3800