A design on the wall of room consists of 1000 tiles of the shape of parallelogram.if altitude and base of each tile is 10 cm and 4 cm respectively,find the cost of polishing the design at the rate of rs 9.50 per dm square
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Answered by
52
Area of one tile = base*altitude
= 10cm*4cm
=40cm square.
Area of 1000 tiles=
40*1000
=40000cm square=40000÷100=400dm square.
Cost of polishing the design= Rs.9.50×400
=3800
= 10cm*4cm
=40cm square.
Area of 1000 tiles=
40*1000
=40000cm square=40000÷100=400dm square.
Cost of polishing the design= Rs.9.50×400
=3800
mathhhhmaster:
the answer will be 38000
Answered by
17
A design on the wall of room consists of 1000 tiles of the shape of parallelogram. If the altitude and base of each tile is 10cm and 4cm respectively.
The cost of polishing the design at the rate of ₹9.50/dm².
We know that,
__________________________________________________________
We know that area of parallelogram:
→ (Base × Altitude) [sq.units]
→ (0.4 × 1)dm²
→ 0.4dm²
→ The total number of tiles consists of room = 1000 tiles.
∴ Total area of the floor = (1000 × 0.4)dm²
→ Total area of the floor = 400dm²
__________________________________________________________
The cost of polishing the design at the rate of ₹9.50/dm².
The cost of polishing the design at the rate = ₹(400 × 9.50)
∴ The cost of polishing the design at the rate is ₹3800.
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