Question

A design on the wall of room consists of 1000 tiles of the shape of parallelogram.if altitude and base of each tile is 10 cm and 4 cm respectively,find the cost of polishing the design at the rate of rs 9.50 per dm square

Answer 1

Area of one tile = base*altitude
= 10cm*4cm
=40cm square.

Area of 1000 tiles=
40*1000
=40000cm square=40000÷100=400dm square.

Cost of polishing the design= Rs.9.50×400
=3800

Answer 2

$\bf{\Huge{\underline{\boxed{\bf{\pink{ANSWER\::}}}}}}$

$\bf{\Large{\underline{\bf{Given\::}}}}$

A design on the wall of room consists of 1000 tiles of the shape of parallelogram. If the altitude and base of each tile is 10cm and 4cm respectively.

$\bf{\Large{\underline{\bf{To\:find\::}}}}$

The cost of polishing the design at the rate of ₹9.50/dm².

$\bf{\Large{\underline{\bf{\orange{Explanation\::}}}}}$

We know that,

$\bf{\boxed{\bf{1cm=0.1dm}}}}$

$\bf{We\:have\begin{cases}\sf{The\:length\:of\:the\:tile=10cm=1dm}\\ \sf{The\:breadth\:of\:the\:tile=4cm=0.4dm}\end{cases}}$

__________________________________________________________

We know that area of parallelogram:

→ (Base × Altitude)    [sq.units]

→ (0.4 × 1)dm²

→ 0.4dm²

→ The total number of tiles consists of room = 1000 tiles.

∴ Total area of the floor = (1000 × 0.4)dm²

→ Total area of the floor = 400dm²

__________________________________________________________

The cost of polishing the design at the rate of ₹9.50/dm².

The cost of polishing the design at the rate = ₹(400 × 9.50)

∴ The cost of polishing the design at the rate is ₹3800.