Question

A design on the wall of room consists of 1000 tiles of the shape of parallelogram. f altitude and base of each tile is 10 cm and 4 cm respectively, find the cost of polishing the design at the rate of 9.50 per dm2.​

Answer 1

Answer:

₹3800.

Step-by-step explanation:

According to the question,

The length of each tile = 10cm

Breadth of each tile= 4cm

Area of each tile=( Length × Breadth )$cm^{2}$

=(10×4) $cm^{2}$

=40 $cm^{2}$

Converting the same to Deci meter($dm^{2}$) as given in the problem we get,

100 $cm^{2}$= 1 $dm^{2}$

40 $cm^{2}$=0.4 $dm^{2}$

Area of each tile in Deci meter = 0.4$dm^{2}$

So the area all the tiles together is= (0.4×1000) $dm^{2}$

=400 $dm^{2}$

Total cost of polishing the tiles= ₹(Total area of tiles × cost per $dm^{2}$)

=₹(400×9.50)

=₹3800.