Question

A design on the wall of room consists of 1000 tiles of the shape of parallelogram. If
altitude and base of each tile is 10 cm and 4 cm respectively, find the cost of polishing
the design at the rate of 9.50 per dm2.​

Answer 1

Answer:

The cost of polishing is rs 3,80,000

Step-by-step explanation:

Given: The length of a tile=10cm.

Base of tile=4cm.

 Since, Area=l×b =10×4 =40$cm^{2}$

Total number of tiles in the room =1000

The total area of the floor =1000×40 =40000$cm^{2}$

 Given that,

Cost of polishing per $cm^{2}$   =rs 9.50/cm

The cost of polishing =40000×9.50 = rs 380000

Answer 2

Given: 1000 Parallelograms of base 10cm and altitude 4cm

To find: The cost of polishing them at the rate of 9.50 per square dm

Solution:

First, we need to find the area of each tile.

$area \: of \: parallelogram = base \times altitude$

$area \: of \: parallelogram = 10 \times 4 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 40cm {}^{2}$

Now, we need to find the area of 1000 tiles of parallelogram.

$area \: of \: 1000 \: tiles = 40 \times 1000 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 40000cm^{2}$

We know that 1 sq cm = 0.01 sq dm. Therefore,

$40000cm {}^{2} = 400dm {}^{2}$

Now, the rate of polishing is 9.50 per sq dm. Therefore,

$rate \: of \: polishing \: of \: 400dm {}^{2} = \frac{400}{9.50} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 42.1$

Here note that the rate didn't have any units and hence the answer would be unitless.

Hence, 42.1 units would be required to polish 1000 tiles in the shape of parallelogram of base 10cm and height 4cm.