(a) Determine the average speed of the train between t=0 s and t = 70 s.
(b) Describe the motion of the train between
(1) t=0 s and t= 10 s;
(H) t= 10 s and t = 70 s;
(III) t = 70 s and t = 90 s.
Solution
(a) Displacement between t= 0 s and t = 70 s Velocity/m s-
= area under velocity-time graph between
15
t=0 s and t= 70 s
= area of shaded trapezium (on the right)
1
X (60 S + 70 s) x 15 m s-1
= 975 m
Average total distance travelled
ol 10
speed
time taken
975 m
70 s
= 13.9 m s-1
explain plz.
Answers
Answered by
1
Answer:
Answer is
Explanation:
Avg speed = 2+ab/a+b
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