Question

a) Determine the power of pump required to lift 300kg of water through a vertical
height of 6m in 9 seconds (Assume g= 10m/s2) (3marks)
(b) A hammer of mass 1500kg drops from a height of 60cm on a pile of mass 750kg.
Determine:- (Assume g= 10m/s2)
(i) The common velocity after impact assuming the hammer does not rebound after impact (5marks)

(ii) The average resistance of the ground if the pile comes to rest after penetrating 5cm into the ground (5marks)

(iii) Time taken for penetration (5marks)

Answer 1

Step-by-step explanation:

Given Determine the power of pump required to lift 300 kg of water through a vertical height of 6 m in 9 seconds

• So we need to find the power of the pump.
• Given Mass m = 300 kg
• So height h = 6m
• Time t = 9 secs
• So we have Power = Work done / Time taken
• So P = W / T
• But W = F x S
• Substituting this we get
•        P = F x S/ T
•      Also F = mg
•           Or P = mgh / T
•                  = 300 x 10 x 6 / 9
•                   = 2000 W
• Or Powe = 2000 Watts

Reference link will be

https://brainly.in/question/6696137