Question

A deuteron and proton are projected in the same electric field. The ratio of acceleration experienced
by them is​

Answer 1

$\bold {\huge {Your ~answer :-}}$

$\bf\huge\boxed{ 1/\:2}$

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EXPLAINATION ➣

Deutron has same charge as proton but mass of deutron is twice that of proton.

So, m(d) = 2m(p) and q(d) = q(p)

We know that Force F = Eq

So, F(d) = Eq(d), F(p) = Eq(p)

And acceleration a = F/m

$\frac{a_d}{a_p} = \frac{ \frac{Eq_d}{2m_p} }{ \frac{Eq_p}{m_p} } = \frac{1}{2}$

Here qd = qp

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