A deuteron of kinetic energy 50 ke v is describing a circular orbit of radius 0.5 m in a plane perpendicular to magnetic field . The kinetic energy of the proton that describes a circular orbit of radius 0.5 m in the same plane with the same is
Answers
Answered by
2
Answer:
a deuteron of kinetic energy 50ke v is describing a circular
Answered by
6
Sorry mate.......!!!
...
I can't understand your question❓❓????
Similar questions