Question

A deuteron of mass 3.2×10^-27kg is balanced by an E.f, then what is the magnitude of E.f, take g=10m/S2?​

Answer 1

Magnitude of Electrostatic force = 2 * 10^-7 V/m

Explanation:

Given: Mass of deuteron = 3.2×10^-27 kg is balanced by an Electrostatic force.

Find: What is the magnitude of Electrostatic force?

Solution:

Taking g = 10 m/s²​

We know that qE = mg

∴E = mg / q

E is the electrostatic force, m is the mass, g is gravity and q is the charge of deuteron.

Deuterons has only 1 proton, so it has a net charge of 1.6 * 10^19

Substituting the values, we get:

E = (3.2 * 10^-27 * 10) / (1.6 * 10^-19)

    = 2 * 10^-7 V/m