A deutron is bombarded on ₈O¹⁶ nucleus and α-particle is emitted. The product nucleus is
(a) ₇N¹³
(b) ₅B¹⁰
(c) ₄BC⁹
(d) ₇N¹⁴
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D. Becoz removal of alpha particle means removal of 2 protons. So 16-2=14
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