Question

a di-positive ion has an electronic arrangement 2,8,8.Find out the number of electrons, protons and neutrons if the mass number is 40​

Answer 1

Answer:

Electronic configuration of dipositive ion is 2,8,8 hence its neutral atom will have configuration as 2,8,8,2, which shows total number of electrons/protnes = 20.

Mass = proton + nutron i.e. 40=20+20

The number of electrons, protons and neutrons in that element = 20,20,20.

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