Question

A diagnol of a quadrilateral is 40m long and the perpendicular to it from the opposite corners are 8 m and 10 m respectively. Then area is

Answer 1

Answer:

Step-by-step explanation:

let the diagonal = d= 4o m

perpendiculars to the diagonal are h1, h2

h1 = 8m

h2 =10m

area of the quadrilateral = (h1+h2)d/2

= (8+10)*40/2

=18*20

=360sq m