A diagnostic test has a probability 0.95 of giving a positive result when applied to a person suffering from a certain disease, and a probability 0.10 of giving a (false) positive when applied to a non-sufferer. It is estimated that 0.5 % of the population are sufferers. Suppose that the test is now administered to a person about whom we have no relevant information relating to the disease (apart from the fact that he/she comes from this population). Calculate the following probabilities:
a. that the test result will be positive
b. that, given a positive result, the person is a sufferer
c. that, given a negative result, the person is a non-sufferer
d. that the person will be misclassified
Answers
Answered by
0
Answer:
I cannot understand that you are not the
Answered by
5
Answer: Let T ≡ “Test positive”, S ≡ “Sufferer”, M ≡ “Misclassified.”
Then P(T|S)=0.95, P(T|S' )=0.10, P(S)=0.005.
Hence (a) P(T) = P(T|S)P(S) + P(T|S' )P(S' ) = (0.95 × 0.005) + (0.1 × 0.995) = 0.10425.
(b) P(S|T) = P(T|S)P(S) P(T|S)P(S) + P(T|S')P(S' ) = 0.95 × 0.005 (0.95 × 0.005) + (0.1 × 0.995) = 0.0455.
(c) P(S' |T' ) = P(T' |S' )P(S' ) P(T' ) = 0.9 × 0.995 1 − 0.10425 = 0.9997.
(d) P(M) = P(T ∩ S' ) + P(T' ∩ S) = P(T|S')P(S' ) + P(T' |S)P(S)=0.09975.
Step-by-step explanation:
Please mark me as brainliest
Similar questions
Chemistry,
1 month ago
Math,
1 month ago
Math,
2 months ago
Computer Science,
2 months ago
Hindi,
9 months ago