Question

A diagonal of a parallelogram bisects one of its angles. Show that it is a rhombus.

Answer 1

rhombus is named as ABCD diagonal AC is drawn ,and as given diagonal bisect one angle so ,
ang ACD = ang ACB ( given) -1
ang ACD =ang CAD ( A.I.A)-2
ang CAD =ang ACB (A.I.A)-3
by 1,2,3
ang CAD = ang CAB
SO,
IN TRNG ADC , ABC
ang CAD=ang CAB
ang ACD =ang ACB
AC is common
si trng ADC is cogruent to ABC
AD =AB
DC=BC
[BY C.P.C.T]
ADJACENT SIDE ARE EQUAL SO IT IS A RHOMBUS

Answer 2

Answer:

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Step-by-step explanation:

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