Question

A diagonal of a parallelogram divides it into 2 congruent triangles. Prove.

Answer 1

Given : ABCD is a parallelogram
           
To prove : ΔACD ≡ ΔACB

proof: In ΔACD and ΔACB
           AB = DC( opposite sides of a parallelogram are equal.)
            AC = AC(common)
           AD = CB (opposite sides of a parallelogram are equal.)

∴ ΔACD ≡ ΔACB

so AC is the diagonal which divides the parallelogram in two congruent part

Answer 2

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