Question

a diagonal of a quadrilateral is 20 CM in length and perpendicular to its form from the opposite vertices are 8.5 metres and 11 metres find the area of quadrilateral ​

Answer 1

Answer:

diagonal = 20cm=1/5m

perpendiculars = 8.5 and 11.5

area of quad. abcd=ar(∆abc) +ar(∆adc)

=1/2×ac×bl + 1/2×ac×dm

=1/2×1/5×8.5 + 1/2×1/5×11

=85+110/5

=195/5

=39 m or 3900 cm

Answer 2

The area of quadrilateral is 1.95 sq. cm.

Step-by-step explanation:

Since we have given that

Perpendicular to its from the opposite vertices = 8.5 m and 11 m

Diagonal = 20 cm = 0.2 m

So, the area of quadrilateral would be

$\dfrac{1}{2}(h_1+h_2)\times d\\\\=\dfrac{1}{2}(8.5+11)\times 0.2\\\\=0.1\times 19.5\\\\=1.95\ cm^2$

Hence, the area of quadrilateral is 1.95 sq. cm.

# learn more:

The diagonal of a quadrilateral is 20 cm in length and the length of perpendicular as it from the opposite vertices are 8.5 cm and 11.5 cm the area of a quadrilateral is​

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