A diagonal of a quadrilateral is 26 cm and the perpendiculars drawn to it from the opposite vertices are 12.8 cm find the area of the quadrilateral
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Answered by
12
area of quadrilateral is 1/2 *d*(h1+h2)
d =26
h1=12.8
h2=11.2
area = 1/2 *26*(12.8+11.2)
= 1/2 *26*24
=1/2*624
=312
d =26
h1=12.8
h2=11.2
area = 1/2 *26*(12.8+11.2)
= 1/2 *26*24
=1/2*624
=312
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2
here is your answer
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if wrong then what is the correct answer or send me pic of that question.
PLEASE MARK IT AS A BRAINLIEST ANSWER.
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