a diagonal of a quadrilateral is 28cm .if the lengths of the perpendiculars on it from the
opposite vertices are 4.5cm,find its area.pls repl, i will mark as brainliest
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area of quadrilateral is 1/2 × diagonal × sum of vertices dropped
area = 1/2 × 28 ×(4.5+4.5)
= 14 × 9
= 126cm²
MARK BRAINLIEST
pranjali05:
It should be 112 not 126
I have the final answer, i wanted steps
but its wrong
What
written by mistake
Im reporting you
Answered by
0
~*HEY FRIEND*~
~* THE ANSWER OF YOUR QUESTION IS..*~
✍✍✍✍✍✍✍✍________________________________________k
given diagonal = 28 cm
area of quadrilateral =
base X diagonl = 28 X 4.5 cm
= 126 cm
as given length of perpendicular is same
so ..you can draw two triangles of equal area...
and by solving this
formula obtained = diagonal X height
HOPE IT WILL HELP YOU
~* THE ANSWER OF YOUR QUESTION IS..*~
✍✍✍✍✍✍✍✍________________________________________k
given diagonal = 28 cm
area of quadrilateral =
base X diagonl = 28 X 4.5 cm
= 126 cm
as given length of perpendicular is same
so ..you can draw two triangles of equal area...
and by solving this
formula obtained = diagonal X height
HOPE IT WILL HELP YOU
Could u pls completely solve
o sorry but im in a hurry
wrong formula
it is given distance of diagonal to a vertice
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