Question

A diagonal of a quadrilateral is 30 cm long and the perpendiculars on it from the opposite vertices are 5.6 cm and 7.4 cm. Find the area of the quadrilateral.​

Answer 1

Answer:

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Answer 2

Answer:

Given:

AB=30cm

AC =5.6cm

BD = 7.4cm

In Ist trinagle ABC ,

Area of right triangle =

$= \frac{1}{2} \times b \times h$

$= \frac{1}{2} \times 30 \times 5.6$

$= 84 {cm}^{2}$

Now ,In 2nd triangle ABD

$= \frac{1}{2} \times b \times h$

$= \frac{1}{2} \times 30 \times 7.4$

$= 111 {cm}^{2}$

Now , the triangle ABC + 2nd triangle ABD

= 84 +111

$= 205 {cm}^{2}$

Step-by-step explanation:

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