Question

A diagonal of a quadrilateral is 40 m long and the
perpendiculars to it from the opposite corners
are 8 m and 10 m respectively. Find its area with figure.

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Answer 1

Answer:

Let the diagonal = d= 4o m

perpendiculars to the diagonal are h1, h2

h1 = 8m

h2 =10m

area of the quadrilateral = (h1+h2)d/2

= (8+10)*40/2

=18*20

=360 sq m