A diagonal of a quadrilateral is 40 m long and the perpendiculars to it from the opposite corners are 8 m and 10 m respectively. Find the area.
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Answer:
let the diagonal = d= 4o m
perpendiculars to the diagonal are h1, h2
h1 = 8m
h2 =10m
area of the quadrilateral = (h1+h2)d/2
= (8+10)*40/2
=18*20
=360sq m
PLZ MARK AS BRIANLIEST AND THX FOR THE SUPERB QUESTION
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