Question

A diagonal of a quadrilateral is 40m long and the perpendiculars to it from the opposite corners are 8m and 10m respectively. Find its area.

Answer 1

Area of 1st triangle = 1/2 * base * height
=1/2* 40*10
=200 sq. M.

Area of 2nd triangle = 1/2* base * height
= 1/2*40*8
=160 sq. M.

Total area = 200+160
=360sq.m

Answer 2

Answer:

360 m2

Step-by-step explanation:

Diagonal = 40m

here diagonal divides the rectangle in to two triangle .

so area of first triangle =1/2×40×8

=160m2

now area of second triangle =1/2×40×10

=200m2

area of rectangle=(160 +200)m2

=360m2