A diagonal of a quadrilateral is 40m long and the perpendicular to it from the opposite corner are 8m and 10m respectively. Find its area
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Solution :-
Let ABCD be a quadrilateral and there are two triangles, Δ ABC and Δ ADC
in it.
Here h1 = 10 m and h2 = 8 m
One of the two diagonals = 40 m
Area of quadrilateral ABCD = Area of Δ ABC + Δ ADC
= 1/2*Base*h1 + 1/2*Base*h2
= 1/2*Base*(h1 + h2)
= 1/2*40*(10 + 8)
= 1/2*40*18
= 720/18
Area of the given quadrilateral = 360 m²
Answer.
Let ABCD be a quadrilateral and there are two triangles, Δ ABC and Δ ADC
in it.
Here h1 = 10 m and h2 = 8 m
One of the two diagonals = 40 m
Area of quadrilateral ABCD = Area of Δ ABC + Δ ADC
= 1/2*Base*h1 + 1/2*Base*h2
= 1/2*Base*(h1 + h2)
= 1/2*40*(10 + 8)
= 1/2*40*18
= 720/18
Area of the given quadrilateral = 360 m²
Answer.
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