Question

A diagonal of a square is 4√2cm . The diagonal of another square whose area is double that of the first square is ?​

Answer 1

Answer:

$\huge\underline\bold {Given:}$

Diagonal of a square = 4√2 cm

$\huge\underline\bold {find?:}$

The diagonal of another square whose area is double that of first square.

$\huge\underline\bold {Answer:}$

Area of square with diagonal 4√2 cm

= 1/2×(diagonal)

= 1/2 × (4√2)^2 cm^2

= 16 cm^2

Area of the second square

= 2 × 16 cm^2

= 32 cm^2

Let d cm be diagonal of the second square. Then

1/2d^2 cm^2

= 32 cm^2

=> d^2 = 2 × 32 cm^2

=> d = √64 cm^2

Therefore the diagonal of another square whose area is double that of the first square is 8 cm.