Question

A diagonal of a square is 4√2cm . The diagonal of another square whose area is double that of the first square is ?​

Answer 1

Answer:

$\huge\underline\bold {Given:}$

Diagonal of a square = 4√2 cm

$\huge\underline\bold {find?:}$

The diagonal of another square whose area is double that of first square.

$\huge\underline\bold {Answer:}$

Area of square with diagonal 4√2 cm

= 1/2×(diagonal)

= 1/2 × (4√2)^2 cm^2

= 16 cm^2

Area of the second square

= 2 × 16 cm^2

= 32 cm^2

Let d cm be diagonal of the second square. Then

1/2d^2 cm^2

= 32 cm^2

=> d^2 = 2 × 32 cm^2

=> d = √64 cm^2

Therefore the diagonal of another square whose area is double that of the first square is 8 cm.

Answer 2

Answer :

8cm

step by step explanation:

let the side of one square : a

diagonal of the square : √2a

according to the question,

diagonal = 4√2 cm

therefore , side of each side of square is 4 cm

=> area of 1st square = a^2 = 4^2 = 16cm^2

as the question say that ,

area of other square is doubled

=> area of of other square = 2(16) = 32 cm^2

=> side of other square = √32 = 4√2 cm

=> diagonal of other square = √2 * 4√2

= 4*2 = 8cm

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