Question

A diagonal of a square is 4√2cm . The diagonal of another square whose area is double that of the square is

Answer 1

LET TAKE THAT SQUARE AS ABCD AND AC AND BD ARE TWO DIAGONAL

IN ∆ADC ^ADC= 90° AND AD = CD
AC² = AD²+AD²
(4√2)² = 2AD²
32 = 2AD²
32/2 = AD²
16 = AD²
4 = AD

AREA OF ABCD IS
= AD²
= 16

AREA OF ONOTHER SQUARE IS
= 16×2
= 32

and length of each sides
32 = a²
4√2 = a

TAKE THAT SQUARE AS EFGH IN EFGH EF = FG = GH = EH = 4√2
AND DIAGONAL ARE EG AND HF

IN ∆ EFG ^EFG = 90°.
FG² = EF²+EF²
FG² = 2EF²
FG² = 2(4√2)²
FG² = 2(32)
FG² = 64
FG = 8

SO THE DIAGONAL LENGTH IS 8CM