A diagonal of rhombus is increased from 16 cm to 18 cm by how much percent is second diagonal should be decreased to get initial area ?
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Answer:
18 cm as diagonal of rhmb are equal
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FIRST CASE
GIVEN ONE DIAGONAL = 16 CM
OTHER DIAGONAL = x CM
AREA OF RHOMBUS =( DIAGONAL 1 x DIAGONAL 2 ) / 2
= 16 x X CM^2
= 16X CM^2
SECOND CASE
GIVEN ONE DIAGONAL = 18 CM
OTHER DIAGONAL = x CM
AREA OF RHOMBUS =( DIAGONAL 1 x DIAGONAL 2 ) / 2
= 18 x X CM^2
= 18X CM^2
PERCENTAGE OF SECOND DIAGONAL TO BE REDUCED = (18 -16) = 2 OF 18 %= 11.111111111111%
SO ANSWER IS 11.111111111111%
PLS MARK BRAINLIEST
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