a diagonal of the rhombus is 80% length of other diagonal then the area of the rhombus is how many times the square of length of longer diagonal?
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Step-by-step explanation:
let the length of longer diagonal be
'x'
one diagonal = 80% of x
= 0.8x
area of the rhombus
= x × 0.8x/2 = 0.4x^2
square of length of longer diagonal
= (x)^2 = x^2
ANS: area of rhombus is 0.4 times the square of the length of longer diagonal .
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