Question

A diagonals of a rhombus measure 16 cm and 30 cm. Find it's perimeter?
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Answer 1

Answer:

Perimeter of Rhombus in form of diagonal

$2\sqrt{16 {}^{2} + {30}^{2} }$

2*root 196+900

2rpot 1096

Answer 2

AC= 16

BD =30cm

OA =OC

OB=OD

in ∆ AOB

AB² =AO² + BO²

AB² = (8)² + (15)²

AB² = 64 + 225

AB²= 289

AB= 17 cm = BC =CD=DA

perimeter = 4× AB = 4×17 = 68

68 is the perimeter of rhombus