Question

A diameter of a circle has endpoints P(-10,-2) and Q(4,6)
a. Find the center of the circle
b. Find the radius. If your answer is not an integer, express it in radical form
c. Write an equation for the circle.

Answer 1

Answer:

-3 , 2

√65

( x + 3)² + (y - 2)² = 65

Step-by-step explanation:

A diameter of a circle has endpoints P(-10,-2) and Q(4,6)

a. Find the center of the circle

b. Find the radius. If your answer is not an integer, express it in radical form

c. Write an equation for the circle.

diameter of a circle has endpoints P(-10,-2) and Q(4,6)

PQ is Diameter

Let say O is center

Co-ordiantes of O  =  ( -10 + 4)/2  , ( -2 + 6)/2

= -3 , 2

Radius = OP = √ (-3 -(-10))² + (2 -(-2))² = √(7² + 4²) = √49 + 16  =√65

( x - a)² + (y-b)² = r²

a & b are co-ordinates of center r = radius

( x -(-3))² + (y - 2)² = (√65)²

=> ( x + 3)² + (y - 2)² = 65