Accountancy, asked by vallemrahul9209, 1 year ago

A diamond falls down and breaks into pieces whose weight are in the ratio 1 : 3 : 6. if the value of the diamond is proportional to the square of its weight, and its original value is rs.30000, what is the loss in value due to breakage

Answers

Answered by pskj018
2

Answer:

16200

Explanation:

30000=10k

k=300

1*300=300

9*300=2700

36*300= 10800

adding all 13800

substact from 30000

ans is 16200

Answered by SmritiSami
1

The answer is ₹ 16200.

Given,

The ratio of weights = 1:3:6

Original value = ₹30000

To Find,

Loss in value due to breakage.

Solution,

Let each unit weight be x

We know that the price is proportional to the square of its weight.

⇒ p ∝ (w)²

Let p₁ be the original price

∴ p₁ = ( x + 3x + 6x)²

  30000 = ( 10x )²

  30000 = 100x²

⇒ x² = 300

Let p₂ be the new value

∴ p₂ = (x)² + (3x)² + (6x)²

  p₂ = x² + 9x² + 36x²

  p₂ = 46x²

  p₂ = 46 (300)

∴ p₂ = ₹13800

∴ Loss = ₹30000 - ₹13800

           = ₹16200

Hence, the loss is ₹ 16,200.  

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