Question

A diamond is immersed in liquid with refractive index greater than water what is the criteria angle

Answer 1

Answer:

For total internal reflection to occur, the incidence angle must be greater than the critical angle.

Critical angle of diamond θ=sin

−1( nd/n a ) =sin −1 ( 2.42/1.00 )=24o

Thus the smallest angle for total internal reflection to occur in diamond is 24o .

Answer 2

Answer:

$sin^{-1} (\frac{2.42}{n} )$

Explanation:

It has been given that:

The refractive index of the liquid is more than the refractive index of water.

We have to find out:

The critical angle for total internal reflection.

Solution:

The refractive index of a diamond is = $2.42$

Now, let the refractive index of liquid = $n$

Critical angle of diamond = α = $sin^{-1} (\frac{2.42}{n} )$

Therefore, the critical angle for total internal reflection is $sin^{-1} (\frac{2.42}{n} )$.

Additional Information:

• Refractive index is also known as the index of refraction and it is the measure of the bending of a ray of light when it passes from one medium to another.
• In optics, the critical angle is the greatest angle at which a ray of light that is taveling in a single transparent medium can strike the boundary between that medium and the second one of the lesser refractive index without being entirely reflected within the first medium.

Final Answer:

The critical angle is $sin^{-1} (\frac{2.42}{n} )$.

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